a)Nếu |x+\(\frac{11}{2}\)|>5
Vậy ta cho x+\(\frac{11}{2}\)=6
x=6-\(\frac{11}{2}\)
x=\(\frac{1}{2}\)
Vậy x>\(\frac{1}{2}\)
b)(x-2)2=1
(x-2)2=12=(-1)2
\(\Rightarrow\left[\begin{array}{nghiempt}x-2=1\\x-2=-1\end{array}\right.\)\(\Rightarrow\)\(\left[\begin{array}{nghiempt}x=3\\x=1\end{array}\right.\)
Vậy x=3;1
a) \(\left|x+\frac{11}{2}\right|>5\) \(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{11}{2}>5\\x+\frac{11}{2}< -5\end{array}\right.\) \(\Rightarrow\left[\begin{array}{nghiempt}x>-\frac{1}{2}\\x< -\frac{21}{2}\end{array}\right.\)
b) \(\left(x-2\right)^2=1\) \(\Leftrightarrow\left[\begin{array}{nghiempt}x-2=1\\x-2=-1\end{array}\right.\) \(\Leftrightarrow\left[\begin{array}{nghiempt}x=3\\x=1\end{array}\right.\)
