Question

Tìm x 

a) \(\left|x+\frac{11}{2}\right|>5\)

b ) \(\left(x-2\right)^2=1\)

Answer 1

a ) \(\left|x+\frac{11}{2}\right|>5\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x+\frac{11}{2}>5\\x+\frac{11}{2}< -5\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x>-\frac{1}{2}\\x< -\frac{21}{2}\end{array}\right.\)

b ) \(\left(x-2\right)^2=1\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x-2=1\\x-2=-1\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=3\\x=1\end{array}\right.\)