Question

Tìm x :

a) \(3-\dfrac{2}{2x-3}=\dfrac{2}{5}+\dfrac{1}{2x-3}-\dfrac{3}{2}\)

b) \(7.\left(x.1\right)+2x.\left(1-x\right)=0\)

c) \(\dfrac{x+1}{2018}+\dfrac{x+2}{2017}+\dfrac{x+3}{2016}=\dfrac{x+10}{2009}+\dfrac{x+11}{2008}+\dfrac{x+12}{2007}\)

Có 3 ý thui các bạn hãy giúp mk!!!!!!

Answer 1

a: \(\Leftrightarrow-\dfrac{3}{2x-3}=\dfrac{2}{5}-\dfrac{3}{2}-3=\dfrac{-41}{10}\)

=>41(2x-3)=30

=>82x-123=30

=>82x=153

hay x=153/82

b: \(\Leftrightarrow\left(x-1\right)\left(7-2x\right)=0\)

=>x=1 hoặc x=7/2

c: \(\Leftrightarrow\left(\dfrac{x+1}{2018}+1\right)+\left(\dfrac{x+2}{2017}+1\right)+\left(\dfrac{x+3}{2016}+1\right)=\left(\dfrac{x+10}{2009}+1\right)+\left(\dfrac{x+11}{2008}+1\right)+\left(\dfrac{x+12}{2007}+1\right)\)

=>x+2019=0

hay x=-2019