Question

a,\(\dfrac{1}{3}\times\left(x-1\right)+\dfrac{2}{5}\times\left(x+1\right)=0\)

b,4x-\(\left(x+\dfrac{1}{2}\right)=2x-\left(\dfrac{1}{2}x-5\right)\)

c,\(\left(x+\dfrac{1}{2}\right)\times\left(x-\dfrac{3}{4}\right)=0\)

Các bn ơi giúp mk với chiều mk đi học rồi !!!!!!!!!!

Answer 1

a. \(\dfrac{1}{3}.\left(x-1\right)+\dfrac{2}{5}.\left(x+1\right)=0\)

=> \(\dfrac{1}{3}x-\dfrac{1}{3}+\dfrac{2}{5}x+\dfrac{2}{5}=0\)

=> \(\dfrac{1}{3}x+\dfrac{2}{5}x=0+\dfrac{1}{3}-\dfrac{2}{5}\)

=> \(\dfrac{11}{15}x=\dfrac{-1}{15}\)

=> \(x=\dfrac{-1}{11}\)

Answer 2

Đây toán 8 mà? :v

a,\(\dfrac{1}{5}x\left(x-1\right)+\dfrac{2}{5}x\left(x+1\right)=0\)

\(\Leftrightarrow5x\left(x-1\right)+6x\left(x+1\right)=0\)

\(\Leftrightarrow\left[5\left(x-1\right)+6x\left(x+1\right)\right]x=0\)

\(\Leftrightarrow\left(5x-5+6x+6\right)x=0\)

\(\Leftrightarrow\left(11+1\right)x=0\)

\(\Leftrightarrow11x+1=0;x=0\)

\(\Leftrightarrow x=-\dfrac{1}{11};x=0\)

Vậy....

Answer 3

bai nay de\

 

 

Answer 4

cho 1like di thi giai theo cach cua co giao day

Answer 5

ko thi vcut

Answer 6

Answer 7