Question

Tìm x

9-16.(4-3x)²=0

Answer 1

\(9-16\left(4-3x\right)^2=0\)

\(\Rightarrow16\left(4-3x\right)^2=9\Rightarrow\left(4-3x\right)^2=\dfrac{9}{16}\)

\(\Rightarrow\left\{{}\begin{matrix}4-3x=-\dfrac{3}{4}\\4-3x=\dfrac{3}{4}\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}3x=\dfrac{19}{4}\\3x=\dfrac{13}{4}\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{19}{12}\\x=\dfrac{13}{12}\end{matrix}\right.\)

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Answer 2

9-16.(4-3x)² =0 \(\Leftrightarrow\) 16.(4-3x)²=9 \(\Leftrightarrow\) (4-3x)²=\(\dfrac{9}{16}\) \(\Leftrightarrow\)\(\left[{}\begin{matrix}4-3x=\dfrac{3}{4}\\4-3x=\dfrac{-3}{4}\end{matrix}\right.\) \(\Leftrightarrow\) \(\left[{}\begin{matrix}3x=4-\dfrac{3}{4}\\3x=4-\left(\dfrac{-3}{4}\right)\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}3x=\dfrac{13}{4}\\3x=\dfrac{19}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{13}{4}:3\\x=\dfrac{19}{4}:3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{13}{12}\\x=\dfrac{19}{12}\end{matrix}\right.\)