Question

tìm x:

(5x-1)(2x-1/3)=0

Answer 1

\(\left(5x-1\right)\left(2x-\dfrac{1}{3}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}5x-1=0\\2x-\dfrac{1}{3}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}5x=1\\2x=\dfrac{1}{3}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=\dfrac{1}{6}\end{matrix}\right.\)

Vậy...........................

Answer 2

vì (5x-1)(2x-1/3)=0

suy ra : 5x-1=0 ; 2x-1/3=0

* 5x-1=0

5x=1

x=1/5

* 2x-1/3=0

2x=1/3

x=2/3

Answer 3

(5x-1).(2x-1/3)=0 <=> 5x-1=0 hoặc 2x-1/3 = 0

5x - 1 = 0 => 5x = 1(số bị trừ bằng hiệu + số trừ)
=> x = 1/5 ( thừa số bằng tích chia thừa số kia)

2x-1/3 = 0 tương tự trên x = 1/6