Question

(5x-1)(2x-1/3)=0

Tìm x ?

P/s: Zúp nha :)) Mình đag cần gấp. Thanks

Answer 1

\(\left(5x-1\right)\left(\frac{2x-1}{3}\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}5x-1=0\\\frac{2x-1}{3}=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}5x=1\\2x-1=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{1}{5}\\2x=1\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{1}{5}\\x=\frac{1}{2}\end{array}\right.\)

Answer 2

(5x - 1)(2x - 1/3) = 0

TH1:

5x - 1 = 0

5x = 1

x = 1/5

TH2:

2x - 1/3 = 0

2x = 1/3

x = 1/3 : 2

x = 1/3 . 1/2

x = 1/6

Vậy x = 1/5 hoặc x = 1/6

Answer 3

\(\left(5x-1\right)\left(2x-\frac{1}{3}\right)=0\)

\(\Rightarrow5x-1=0\) hoặc \(2x-\frac{1}{3}=0\)

Nếu \(5x-1=0\)

\(5x=0+1\)

\(5x=1\)

\(x=\frac{1}{5}\)

Nếu \(2x-\frac{1}{3}=0\)

\(2x=0+\frac{1}{3}\)

\(2x=\frac{1}{3}\)

\(x=\frac{1}{6}\)

Vậy \(x=\frac{1}{5}\) hoặc \(x=\frac{1}{6}\)

Answer 4

( 5x- 1) (2x -1/3)

=> TH1: 5x-1= 0

=>              5x= 0+ 1

=>              5x= 1

=>              x= 1/5

=> TH2: 2x- 1/3= 0

=>               2x= 0+ 1/3

=>               2x= 1/3

=>               x= 1/3: 2

=>               x=1/6

Vậy x= 1/5 hoặc 1/6