\(32^{-x}\times16^x=1024\\ 16^{-x}\times2^{-x}\times16^x=2^{10}\\ \left(16^{-x}\times16^x\right)\times2^{-x}=2^{10}\\ 2^{-x}=2^{10}\\ \Rightarrow-x=10\\ x=-10\) \(\left(\dfrac{4}{5}\right)^{2x+7}=\dfrac{625}{256}\\ \left(\dfrac{4}{5}\right)^{2x+7}=\left(\dfrac{4}{5}\right)^{-4}\\ \Rightarrow2x+7=4\\ 2x=-3\\ x=-1,5\)
Tìm x biết :
a. 32-x .16x = 1024
b. (\(\dfrac{4}{5}\))2x+7 = \(\dfrac{625}{256}\)
\(\dfrac{2^{18}}{32^3}.\dfrac{27^4}{54^3}\) \(\dfrac{x+1}{9}=\dfrac{4}{x+1}\) Tìm x, y biết:
\(\dfrac{40^4}{120^4}:\dfrac{130^3}{390^3}\) \(19.5^{2x+7}=475\) 5x=4y và y-x=7
\(2^x.8\) \(\dfrac{2x}{5}=\dfrac{10}{x}\)
\((\dfrac{1}{2})^x=\dfrac{1}{32}\) \(33^x:11^x=243\)
a,\(4\dfrac{1}{3}:\dfrac{x}{4}=6:0,3\)
b, \(\left(x-1\right)^5=-32\)
c, \(\left(2^3:4\right).2^{x+1}=64\)
d, \(|3-2x|-3=-3\)
e, \(|x+\dfrac{4}{5}|-\dfrac{1}{7}=0\)
| 1)\(\dfrac{2^{18}}{32^3}.\dfrac{27^4}{54^3}\) | 4)\((\dfrac{1}{2})^x=\dfrac{1}{32}\) |
| 2)\(\dfrac{40^4}{120^4}.\dfrac{130^3}{390^3}\) | 5)\(\dfrac{x+1}{9}=\dfrac{4}{x+1}\) |
| 3)\(2^x=8\) | 6)\(\dfrac{2x}{5}=\dfrac{10}{x}\) |
| 7)\(19.5^{2x+7}=475\) | |
| 8)\(33^x:11^x=243\) | |
| 9)Tìm x, y biết: 5x=4y và y-x=7 |
1. tìm x
a, 2x - \(\dfrac{1}{2}\) : \(\dfrac{3}{4}\) = \(\dfrac{12}{9}\)
b, x\(^2\) - 2 = 0
2. Cho
A = \(\dfrac{1,11+0,19-13.2}{2,06+0,54}\) - \(\left(\dfrac{1}{2}+\dfrac{1}{4}\right)\) : 2
B = \(\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right)\) : \(2\dfrac{23}{26}\)
a, Rút gọn A, B
b, Tìm x ϵ Z để A < x < B
\(\dfrac{1}{3}\) . ( x - 2 ) - \(\dfrac{3}{4}\) x = 1
\(\dfrac{x+3}{x-4}\) = \(\dfrac{5}{12}\) ( x ≠ 4 )
\(\dfrac{x-2}{x+3}\) = \(\dfrac{x-5}{x-7}\)
( 3x + 2 )\(^4\) = 81
\(2^{x-3}\) = \(1024^4\)
\(3^x\) + 5 . \(3^{x-1}\) = 648
( x - 2,5 )\(^2\) = \(\dfrac{4}{9}\)
\(\left(2x+\dfrac{1}{3}\right)^3\) = \(-\dfrac{8}{27}\)
\(\dfrac{2}{3}\) . \(3^{x+1}\) - 7 . \(3^x\) = -405
tìm x, y, z biết
a) \(\dfrac{x}{7}=\dfrac{y}{5}=\dfrac{z}{3}\) và 2x+3y-5z=28
b) 3x=2y, 7y=5z và x-y+z=32
Tìm x biết :
1) \(\dfrac{-7}{x+1}=\dfrac{-x-1}{\dfrac{4}{7}}\)
2) \(\dfrac{x-3}{x+5}=\dfrac{5}{7}\)
3) \(\dfrac{x+1}{2x+1}=\dfrac{0,5x+2}{x+3}\)
4) \(\dfrac{3x+2}{5x+7}=\dfrac{3x-1}{5x+1}\)
1,tìm x, biết
a,\(4\dfrac{1}{3}_{ }\):\(\dfrac{x}{4}\)=6:0,3
b (\(2^3\):4).\(2^{x+1}\)=64
c, (x-1)\(^5\)=-32
d, \(|3-2x|-3=-3\)
e, \(|x+\dfrac{4}{5}|-\dfrac{1}{7}=0\)
2, Tìm x,y,z biết:
2x=3y=6z
Và x+y+z=1830
