\(\dfrac{1}{2}x+\dfrac{3}{5}\left(x-2\right)=3\Leftrightarrow\dfrac{1}{2}x+\dfrac{3}{5}x-\dfrac{6}{5}=3\)
\(\Leftrightarrow\dfrac{11}{10}x=\dfrac{21}{5}\Leftrightarrow11x=42\Leftrightarrow x=\dfrac{42}{11}\)
vậy \(x=\dfrac{42}{11}\)
tim x ,a,x+1/2:(-3/4)=-5/4
b,1-(5 3/8 +x-7 5/24):16 2/3=0
Tim x biet:
a,32.x=81
b,52.x-3-2=10
c,(5x-1).3-2=10
tim x biet:
( 1/2 +1/3+ 1/4+ 1/5+ 1/6 +1/7)x (2009 * x ) = 0.63* 0.12 - 2,1 * 0,036
tim x
(x-2)(5-x)>0
(x-3)(x-7)<0
x-1/x-9>0
Tim x thuoc N biet
(7x-11)3=25.52 +200. ;b)3x+25=26.22+2.30.
2x+3.2=64 ;5x+1+5x=750
x15=x ;(x-5)4=(x-5)6
tim x : 1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)-1/1/2010
+Tim x :
a ) \(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
b )\(\left(x+\frac{1}{2}\right)^2=\frac{4}{25}\)
c ) \(\left(x+1\right)^{x+2}=\left(x-1\right)^{x+6}\) (x ϵ Z )
d ) \(\left(2x+3\right)^{2016}=\left(2x+3\right)^{2018}\)
e ) \(\frac{3}{x+2.x+5}+\frac{5}{x+5.x+10}+\frac{7}{x+10.x+17}=\frac{x}{x+2.x+17}\) Với \(x\notin\left\{-2;-5;-10;-17\right\}\)
Bai 1: Tim x
a)\(4^5+4^5+4^5+4^5.6^5+6^5+6^5+6^5+6^5+6^5=2^x\)
b)\(x\left(x+3\right)^{100}\)\(=\left(x+3\right)^{100}\)
tim x biet -2/3 (x-1/4)=1/3( 2x -1)
