Question

Tìm X

(12x-5)(4x-1)+(3x-7)(1-16x)=81

Answer 1

(12x-5)(4x-1)+(3x-7)(1-16x) = 81

\(48x^2-12x-20x+5+3x-48x^2-7+112x-81=0\)

83x = 83

x = 1

Answer 2

\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)

\(\Rightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\)

\(\Rightarrow\left(48x^2-48x^2\right)+\left(-12x-20x+3x+112x\right)=81-5+7\)

\(\Rightarrow83x=83\Rightarrow x=1\)

Vậy \(x=1\)

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