Question

tìm tỉ số \(\frac{x}{y}\)biết \(\frac{x-y}{x+2y}=\frac{3}{4}\)

Answer 1

\(\frac{x-y}{x+2y}=\frac{3}{4}\)

4(x - y) = 3(x + 2y)

4x - 4y = 3x + 6y

4x - 3x = 6y + 4y

x = 10y

\(\frac{x}{y}=\frac{10}{1}\)

Answer 2

\(\frac{x-y}{x+2y}=\frac{3}{4}\)

\(\Leftrightarrow4\left(x-y\right)=3\left(x+2y\right)\)

\(\Leftrightarrow4x-4y=3x+6y\)

\(\Leftrightarrow x=10y\)

\(\Leftrightarrow\frac{x}{y}=10\)

Answer 3

\(\frac{x-y}{x+2y}=\frac{3}{4}\)

\(\Rightarrow4\left(x-y\right)=3\left(x+2y\right)\)

\(\Rightarrow4x-4y=3x+6y\)

\(\Rightarrow4x-3x=6y+4y\)

\(\Rightarrow x=10y\)

\(\Rightarrow\frac{x}{y}=\frac{1}{10}\)

Vậy \(\frac{x}{y}=\frac{1}{10}\)

Answer 4

\(\frac{x-y}{x+2y}\)=\(\frac{3}{4}\)

=>4(x-y)=3(x+2y)

=>4x-4y=3x+6y

=>4x-3x=4y+6y

=>1x=10y

=>\(\frac{10}{1}\)=\(\frac{x}{y}\)

Vậy tỉ số \(\frac{x}{y}\)=\(\frac{10}{1}\)