Giải:
\(\dfrac{1}{9}.27^n=3^n\)
\(\Leftrightarrow\dfrac{27^n}{9}=3^n\)
\(\Leftrightarrow\dfrac{3^{3n}}{3^2}=3^n\)
\(\Leftrightarrow3^n.3^2=3^{3n}\)
\(\Leftrightarrow3^{n+2}=3^{3n}\)
Vì \(3=3\)
Nên \(n+2=3n\)
\(\Leftrightarrow n-3n=-2\)
\(\Leftrightarrow-2n=-2\)
\(\Leftrightarrow n=1\)
Vậy \(n=1\).
Chúc bạn học tốt!!!