Ta có:
\(\frac{x-2}{2x^2+3}=\frac{2x^2-4x}{Q}\)
\(\Leftrightarrow\frac{x-2}{2x^2+3}=\frac{2x\left(x-2\right)}{Q}\)
\(\Leftrightarrow Q=\frac{2x\left(x-2\right)\left(2x^2+3\right)}{x-2}\)
\(\Leftrightarrow Q=2x\left(2x^2+3\right)\)
\(\Leftrightarrow Q=4x^3+6x\)
Vậy \(Q=4x^3+6x\)
Chúc bạn học tốt@@
\(Q=2x\cdot\left(2x^2+3\right)\)