\(n-3⋮n+2\)
\(\Rightarrow n-3=n+2-5\)
Vì \(n+2⋮n+2\) để \(n-3⋮n-2\) thì \(5⋮n-2\)
\(n+2\in U\left(5\right)\)
Ư(5) = \(\left\{\pm1;\pm5\right\}\)
Ta có :
n+2 = 1 => n = -1(tm)
n + 2 = -1 => n = -3 (tm)
n + 2 = 5 => n = 3 (tm)
n + 2 = -5 => n = -7 (tm)
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