Question

Tìm n , biết

\(\left(8x-1\right)^{2n+1}=5^{2n+1}\)

Answer 1

\(\left(8x-1\right)^{2n+1}=5^{2n+1}\)

\(\Leftrightarrow8x-1=5\)

\(\Leftrightarrow x=\frac{3}{4}\)

Answer 2

\(\left(8x-1\right)^{2n+1}=5^{2n+1}\)

\(\Rightarrow8x-1=5\)

\(\Rightarrow8x=6\)

\(\Rightarrow x=\frac{3}{4}\)

Vậy \(x=\frac{3}{4}\)