Lời giải:
\(E=100x^2+16y^2-8y+29=(10x)^2+(16y^2-8y+1)+28\)
\(=(10x)^2+(4y-1)^2+28\)
Vì \((10x)^2\geq 0; (4y-1)^2\geq 0, \forall x,y\in\mathbb{R}\)
\(\Rightarrow E\geq 0+0+28=28\)
Vậy \(E_{\min}=28\Leftrightarrow 10x=4y-1=0\Leftrightarrow x=0; y=\frac{1}{4}\)