Ta có \(\sqrt{x}\ge0\) với mọi x \(\ge\) 0
\(\Rightarrow\sqrt{x}+4\ge4\)
\(\Rightarrow\dfrac{5}{\sqrt{x}+4}\le\dfrac{5}{4}\)
\(\Rightarrow\dfrac{-5}{\sqrt{x}+4}\ge\dfrac{-5}{4}\)
\(\Rightarrow P\ge\dfrac{-5}{4}\)
Dấu "=" xảy ra \(\Leftrightarrow x=0\)