ĐKXĐ:...
\(A=x-\sqrt{x-2016}=x-2016-\sqrt{x-2016}+\frac{1}{4}+\frac{8063}{4}\)
\(A=\left(\sqrt{x-2016}-\frac{1}{2}\right)^2+\frac{8063}{4}\ge\frac{8063}{4}\)
\(A_{min}=\frac{8063}{4}\) khi \(x-2016=\frac{1}{4}\Rightarrow x=...\)
\(B=x+\sqrt{x}+1\)
Do \(x\ge0\Rightarrow x+\sqrt{x}\ge0\Rightarrow B\ge1\)
\(B_{min}=1\) khi \(x=0\)