A = x2 + 4x + 6 = (x2 + 4x + 4) + 2 = (x + 2)2 + 2 \(\ge\) 2. Dấu "=" xảy ra <=> x = -2
B = 9x2 - 6x + 3 = (9x2 - 6x + 1) + 2 = (3x - 1)2 + 2 \(\ge\) 2. Dấu "=" xảy ra <=> x = \(\dfrac{1}{3}\)
C = -x2 + 8x + 25 = -(x2 - 8x + 16) + 41 = -(x - 4)2 + 41 \(\le\) 41. Dấu "=" xảy ra <=> x = 4
D = -x2 + 6x = -(x2 - 6x + 9) + 9 = -(x - 3)2 + 9 \(\le\) 9. Dấu "=" xảy ra <=> x = 3