Ta có:
\(x+y=1\)
\(\Rightarrow\left\{{}\begin{matrix}x=1-y\\y=1-x\end{matrix}\right.\)
\(\Rightarrow xy=\left(1-y\right)\left(1-x\right)\)
\(\Rightarrow xy=\left(1-y\right)-\left(1-y\right)x\)
\(\Rightarrow xy=1-y-x+xy\)
\(\Rightarrow xy=xy+1-\left(x+y\right)\)
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