2. Tìm x biết:
a)2(x+2)(x+4)\dfrac{2}{\left(x+2\right)\left(x+4\right)} + 4(x+4)(x+8)\dfrac{4}{\left(x+4\right)\left(x+8\right)} + 6(x+8)(x+14)\dfrac{6}{\left(x+8\right)\left(x+14\right)} = x(x+2)(x+14)\dfrac{x}{\left(x+2\right)\left(x+14\right)}
b)x2023\dfrac{x}{2023} + x+12022\dfrac{x+1}{2022} x+22021\dfrac{x+2}{2021} +...+ x+20221\dfrac{x+2022}{1} + 2023 = 0.
Gíup mình giải 2 bài này với!
Cảm ơn các bạn rất nhiều!!!
Tìm x,biết
a, \(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
Với x ∉ -2,-5,-10,-17
b,\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
Với x∉1,3,8,20
c,\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
Tìm GTLN của A=\(\frac{1}{\left|x+2017\right|+\left|x-2\right|}\)
Bài 1 : Tìm \(x,y,z\in Q\)
\(a)\left|x-3,5\right|+\left|4,5-y\right|=0\)
\(b)\left|x-2\right|+\left|3-y\right|=0\)
\(c)\left|x+\frac{2}{3}\right|+\left|y-\frac{3}{4}\right|+\left|z-5\right|=0\)
\(d)\left|x+\frac{13}{14}\right|+\left|x-\frac{3}{7}\right|=0\)
giúp mình với ❤❤❤
Tìm x
a, \(\frac{1}{3}x-\frac{2}{5}.\left(x+1\right)=0\)
b, \(\frac{x+2}{0,5}=\frac{2x+1}{2}\)
c, \(|x+\frac{1}{5}|-4=2\)
d, \(\left(\frac{1}{4}x-1,5\right)+\left(\frac{5}{6}x-3\right)-\left(\frac{5}{8}x-0,5\right)=-4,5\)
Tìm x, biết:
a) \(\left(\frac{-3}{4}\right)^{3x-1}=\frac{-27}{64}\)
b) \(\left(\frac{4}{5}\right)^{2x+5}=\frac{256}{265}\)
c) \(\frac{\left(x+3\right)^5}{\left(x+3\right)^2}=\frac{64}{27}\)
d) \(\left(x-\frac{2}{15}\right)^3=\frac{8}{125}\)
a, cho biểu thức P= x-4xy+y .Tinh giá trị của P với \(\left|x\right|=1,5;y=-0,75\)
b, Rút gọn biểu thức: A=\(\dfrac{2^{12}\cdot3^5-4^6\cdot81}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}\)
a)\(\left(x-\frac{2}{3}\right)\). \(\left(x+\frac{1}{4}\right)\)= 0
b) \(\left(x-\frac{2}{3}\right)\). \(\left(2x-\frac{3}{4}\right)\) = \(\left(3x+\frac{1}{2}\right)\). \(\left(x+\frac{2}{3}\right)\)
bài 2:tìm x giá trị biểu thức
a)2-\(|^{ }_{ }\)3x-\(\frac{1}{4}|\)=\(\left|-\frac{5}{4}\right|\) f)-2,5:\(\left|\frac{3}{4}x+\frac{1}{2}\right|=3\)
b)5-3.\(\left|5-2x\right|\)=-4,5 g)\(\left|2x-5\right|=\left|x=1\right|\)
c)\(\frac{3}{2}+\frac{3}{4}.\left|x-\frac{3}{4}\right|=\frac{7}{4}\)
d)\(\frac{11}{4}+\frac{3}{2}\left|4x-\frac{1}{5}\right|=\frac{7}{2}\)
e)\(\frac{21}{5}+3:\left|\frac{x}{4}-\frac{2}{3}\right|=6\) h)\(\left|\right|2x+1|-3|=\left|-5\right|\)