\(A=\frac{36\sqrt{x}-117}{9\left(\sqrt{x}-1\right)^2}=\frac{4\left(\sqrt{x}-1\right)^2-4x+44\sqrt{x}-121}{9\left(\sqrt{x}-1\right)^2}=\frac{4}{9}-\frac{\left(2\sqrt{x}-11\right)^2}{9\left(\sqrt{x}-1\right)^2}\le\frac{4}{9}\)
\(A_{max}=\frac{4}{9}\) khi \(x=\frac{121}{4}\)
Tìm GTLN của A
\(A=\frac{4\sqrt{x}-13}{\left(\sqrt{x}-1\right)^2}\)