A = \(\dfrac{2x+1}{x^2+2}\)
=> 2A = \(\dfrac{4x+2}{x^2+2}\)
= \(\dfrac{\left(x^2+4x+4\right)-\left(x^2+2\right)}{x^2+2}\)
= \(\dfrac{x^2+4x+4}{x^2+2}-1\)
= \(\dfrac{\left(x+2\right)^2}{x^2+2}-1\ge-1\)
=> 2A \(\ge-1\)
=> A \(\ge\) \(-\dfrac{1}{2}\)
Dấu "=" xảy ra khi x = -2