\(P=\dfrac{2x^2-2x+5}{x^2-4x+4}=\dfrac{x^2-4x+4+x^2+2x+1}{x^2-4x+4}=1+\dfrac{\left(x+1\right)^2}{\left(x-2\right)^2}\)Do : \(\dfrac{\left(x+1\right)^2}{\left(x-2\right)^2}\) ≥ 0 ∀x
⇒ \(\dfrac{\left(x+1\right)^2}{\left(x-2\right)^2}\) + 1 ≥ 1
⇒ \(P_{Min}=1\) ⇔ x = - 1
P/s : Day la tim GTNN nha