ĐKXĐ: \(x\ge0\)
\(P=\dfrac{\sqrt{x}-1}{\sqrt{x}+2}\Rightarrow P\sqrt{x}+2P=\sqrt{x}-1\)
\(\Rightarrow\sqrt{x}\left(P-1\right)=-1-2P\Rightarrow\sqrt{x}=\dfrac{2P+1}{1-P}\)
Do \(\sqrt{x}\ge0\Rightarrow\dfrac{2P+1}{1-P}\ge0\Rightarrow\dfrac{-1}{2}\le P< 1\)
\(\Rightarrow P_{min}=\dfrac{-1}{2}\) khi \(x=0\)