Ta có: \(2\left|3x-6\right|\ge0\)
\(\Rightarrow B=2\left|3x-6\right|-4\ge-4\)
Dấu " = " khi \(2\left|3x-6\right|=0\Rightarrow x=2\)
Vậy MIN B = -4 khi x = 2
Ta co : 2.| 3x - 6 | \(\ge\) 0 \(\Rightarrow\)2.|3x-6| -4 \(\ge\)-4 dau "= " xay ra \(\Leftrightarrow\) 2.|3x-6| =0 \(\Leftrightarrow\) 3x-6=0 \(\Leftrightarrow\) x=2 vay Min ( A) = -4 \(\Leftrightarrow\) x=2