Ta có:
\(\dfrac{1}{b+1}+\dfrac{1}{b\left(b+1\right)}=\dfrac{b}{b\left(b+1\right)}+\dfrac{1}{b\left(b+1\right)}=\dfrac{b+1}{b\left(b+1\right)}=\dfrac{1}{b}\)
áp dụng ta có:
\(\dfrac{1}{5}=\dfrac{1}{5+1}+\dfrac{1}{5\left(5+1\right)}=\dfrac{1}{6}+\dfrac{1}{30}\)
Vậy x = 6, y = 30 hoặc x = 30 và y = 6