\(P=sin^4x-cos^4x=\left(sin^2x+cos^2x\right)\left(sin^2x-cos^2x\right)\)
\(\Rightarrow P=-\left(cos^2x-sin^2x\right)=-cos2x\)
Do \(-1\le cos2x\le1\Rightarrow-1\le P\le1\)
\(\Rightarrow\left\{{}\begin{matrix}P_{min}=-1\Rightarrow x=k\pi\\P_{max}=1\Rightarrow x=\frac{\pi}{2}+k\pi\end{matrix}\right.\)
b/
\(P=sin^6x+cos^6x=\left(sin^2x+cos^2x\right)\left(sin^4x+cos^4x-sin^2x.cos^2x\right)\)
\(P=sin^4x+cos^4x+2sin^2x.cos^2x-3sin^2x.cos^2x\)
\(P=\left(sin^2x+cos^2x\right)^2-\frac{3}{4}\left(2sinx.cosx\right)^2\)
\(P=1-\frac{3}{4}sin^22x\)
Do \(0\le sin^22x\le1\Rightarrow\frac{1}{4}\le P\le1\)
\(\Rightarrow\left\{{}\begin{matrix}P_{min}=\frac{1}{4}\Rightarrow x=\frac{k\pi}{4}\\P_{max}=1\Rightarrow x=\frac{k\pi}{2}\end{matrix}\right.\)
c/
\(P=1-2\left|cos3x\right|\)
Do \(0\le\left|cos3x\right|\le1\Rightarrow-1\le P\le1\)
\(\Rightarrow\left\{{}\begin{matrix}P_{min}=-1\Rightarrow x=\frac{k\pi}{3}\\P_{max}=1\Rightarrow x=\frac{k\pi}{6}\end{matrix}\right.\)