\(\dfrac{1}{6\left(1-3x\right)}-\dfrac{1}{\left(3x-1\right)^2}+\dfrac{1}{6\left(3x+11\right)}+\dfrac{3}{\left(3x+11\right)^2}=0\)
\(\Leftrightarrow\dfrac{-1}{6\left(3x-1\right)}-\dfrac{1}{\left(3x-1\right)^2}=\dfrac{-1}{6\left(3x+1\right)}-\dfrac{3}{\left(3x+11\right)^2}\)
\(\Leftrightarrow-\left(3x-1\right)-6=-1\left(3x+11\right)-18\)
=>-3x+1-6=-3x-11-18
=>-3x-5=-3x-19
=>-5=-19(vô lý)