\(\begin{array}{l}a){\rm{ }}3{x^2}-{\rm{ }}3x\left( {x{\rm{ }}-{\rm{ }}2} \right){\rm{ }} = {\rm{ }}36\\ \Leftrightarrow 3{x^2}-{\rm{ [}}3x.x + 3x.( - 2)] = 36\\ \Leftrightarrow 3{x^2} - (3{x^2} - 6x) = 36\\ \Leftrightarrow 3{x^2} - 3{x^2} + 6x = 36\\ \Leftrightarrow 6x = 36\\ \Leftrightarrow x = 36:6\\ \Leftrightarrow x = 6\end{array}\)
Vậy x = 6
\(\begin{array}{l}b){\rm{ }}5x\left( {4{x^2}-{\rm{ }}2x{\rm{ }} + {\rm{ }}1} \right){\rm{ }}-{\rm{ }}2x\left( {10{x^2}-{\rm{ }}5x{\rm{ }} + {\rm{ }}2} \right){\rm{ }} = {\rm{ }} - 36\\ \Leftrightarrow 5x.4{x^2} + 5x.( - 2x) + 5x.1 - [2x.10{x^2} + 2x.( - 5x) + 2x.2] = - 36\\ \Leftrightarrow 20{x^3} - 10{x^2} + 5x - (20{x^3} - 10{x^2} + 4x) = - 36\\ \Leftrightarrow 20{x^3} - 10{x^2} + 5x - 20{x^3} + 10{x^2} - 4x = - 36\\ \Leftrightarrow (20{x^3} - 20{x^3}) + ( - 10{x^2} + 10{x^2}) + (5x - 4x) = - 36\\ \Leftrightarrow x = - 36\end{array}\)
Vậy x = -36