goi cong thuc hhoa hoc tong quat la CxOy
Theo de bai ta co
nC=\(\dfrac{3}{12}=0,25\)mol \(\Rightarrow\)x=0,25
nO=\(\dfrac{8}{16}=0,5mol\)\(\Rightarrow\)y=0,5
\(\Rightarrow\)Ta co ti le
x:y=0,25:0,5
=1:2
vay x=1 y=2 \(\Rightarrow\)Cthh cua oxit la CO2
Ten goi la Cacbondioxit
C