\(6x+5y+18=2xy\\ \Leftrightarrow2xy-6x+15-5y=33\\ \Leftrightarrow2x\left(y-3\right)-5\left(y-3\right)=33\\ \Leftrightarrow\left(2x-5\right)\left(y-3\right)=33\)
Ta có:
| \(2x-5\) | ±33 | ±1 | ±3 | ±11 |
| \(y-3\) | ±1 | ±33 | ±11 | ±3 |
| \(x\) | 19;-14 | 3;2 | 4;1 | 8;-3 |
| \(y\) | 4;2 | 36;-30 | 14;-8 | 6;0 |
Vậy \(\left(x;y\right)=\left\{\left(19;4\right);\left(-14;2\right);\left(3;36\right);\left(2;-30\right);\left(4;14\right);\left(1;-8\right);\left(8;6\right);\left(-3;0\right)\right\}\)
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