\(\widehat{A}:\widehat{B}:\widehat{C}=3:4:5\\ \Rightarrow\dfrac{\widehat{A}}{3}=\dfrac{\widehat{B}}{4}=\dfrac{\widehat{C}}{5};\widehat{A}+\widehat{B}+\widehat{C}=180^0\)
Áp dụng t/c dãy tsbn:
\(\dfrac{\widehat{A}}{3}=\dfrac{\widehat{B}}{4}=\widehat{\dfrac{C}{5}}=\dfrac{\widehat{A}+\widehat{B}+\widehat{C}}{3+4+5}=\dfrac{180^0}{12}=15\\ \Rightarrow\left\{{}\begin{matrix}\widehat{A}=45^0\\\widehat{B}=60^0\\\widehat{C}=75^0\end{matrix}\right.\)
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