\(\dfrac{3}{4}\cdot44\dfrac{1}{5}-\dfrac{3}{4}\cdot28\dfrac{1}{5}\)
=\(\dfrac{3}{4}\cdot\left(44\dfrac{1}{5}-28\dfrac{1}{5}\right)\)
=\(\dfrac{3}{4}\cdot16\)
=12
\(\dfrac{3}{4}\cdot44\dfrac{1}{5}-\dfrac{3}{4}\cdot28\dfrac{1}{5}\)
=\(\dfrac{3}{4}\cdot\left(44\dfrac{1}{5}-28\dfrac{1}{5}\right)\)
=\(\dfrac{3}{4}\cdot16\)
=12
Các bạn ơi giúp mình vs T-T
1) A = \(\dfrac{15}{24}+\dfrac{7}{21}+\dfrac{9}{34}-1\dfrac{15}{17}+\dfrac{2}{3}\)
2) B = \(16\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)-28\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)\)
3) C = \(25.\left(-\dfrac{1}{3}\right)^3+\dfrac{1}{5}-2.\left(-\dfrac{1}{2}\right)^2-\dfrac{1}{2}\)
4) D = \(\left(-2\right)^3.\left(\dfrac{3}{4}-0,25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
5) E = \(5\sqrt{6}-4\sqrt{9}+\sqrt{25}-0,3\sqrt{400}\)
a) \(\dfrac{11}{13}-\left(\dfrac{5}{42}-x\right)=\left(\dfrac{15}{28}-\dfrac{11}{13}\right)\)
b) \(\left(\dfrac{7}{2}-2x\right)x3\dfrac{2}{5}+1\dfrac{4}{5}=7\dfrac{6}{5}\)
c) \(\left|2x-\dfrac{1}{3}\right|=\dfrac{5}{3}-2\)
d) (2x-1)3= -27
e) \(\dfrac{16}{2x}=1\)
tìm x, biết:
a.\(\dfrac{5}{12}\sqrt{x}-\dfrac{1}{6}=\dfrac{1}{3}\)
b. \(\left|\dfrac{3}{4}x-\dfrac{3}{4}\right|-\dfrac{3}{4}=\left|\dfrac{-3}{4}\right|\)
giúp mk nhanh nha đan cần gấp
CMR:a)\(\dfrac{1}{3}< \dfrac{1}{11}+\dfrac{1}{12}+\dfrac{1}{13}+....+\dfrac{1}{30}< \dfrac{5}{2}\)
b)\(\dfrac{1}{5}< \dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{5}+.....-\dfrac{1}{99}< \dfrac{2}{5}\)
c)\(\dfrac{1}{15}< \dfrac{1}{2}.\dfrac{3}{4}......\dfrac{99}{100}< \dfrac{1}{10}\)
Bài 1:Thực hiện phép tính.
1) \(\dfrac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\) ; 2)\(\dfrac{15^3+5\cdot15^2-5^3}{18^2+6\cdot18^2-6^3}\)
Bài 2:Tìm x, biết:
1)\(^{\left(5x+1\right)^2}\)=\(\dfrac{36}{49}\) ; 2) \(2^{x-1}=16\) ; 3)\(\left(-\dfrac{3}{4}\right)^{3x-1}=-\dfrac{27}{64}\) ; 4)\(\dfrac{-1}{2}+\dfrac{5}{x+3}=\dfrac{-5}{6}\)
5)\(\dfrac{37-x}{x+13}=\dfrac{3}{7}\) ; 6)\(\dfrac{1}{12}:\dfrac{4}{21}=3\dfrac{1}{2}:\left(3x-2\right)\) ; 7) \(^{2^{2x+1}+4^{x+3}=264}\) ; 8) \(\dfrac{x+7}{-20}=\dfrac{-5}{x+7}\)
9) \(\dfrac{x}{8}=\dfrac{x}{x^3}\) ; 10) \(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
Mọi người giúp mình với,làm ơn !!!!!
I. Tính
1) (1+\(\dfrac{2}{3}\)-\(\dfrac{1}{4}\)). 0,8- \(\dfrac{3}{4}\))\(^2\)
2) (2\(^2\): \(\dfrac{4}{3}\)-\(\dfrac{1}{2}\)).\(\dfrac{6}{5}\)-17
3)24\(\dfrac{1}{7}\):\(\dfrac{-3}{5}\)-33\(\dfrac{1}{7}\):\(\dfrac{-3}{5}\)
Tính
\(\left(-0,75.\dfrac{-1}{4}\right):\left(-5\right)+\dfrac{1}{5}+\dfrac{1}{5}-\left(\dfrac{-1}{5}\right):\left(-3\right)\)
a)\(\dfrac{x+1}{2}\)=\(\dfrac{2x+3}{5}\)
b)\(\left|x-1\right|\) + 3\(\left|y+1\right|\) + \(\left|z+2\right|=0\)
c)\(\dfrac{x-2}{4}=\dfrac{5-3x}{4}\)
d)\(\dfrac{x+2}{4}=\dfrac{4}{x+2}\)
e)\(\dfrac{x-1}{5}=\dfrac{-20}{x-1}\)
a/\(\left(\dfrac{-3}{7}+\dfrac{5}{11}\right)\):\(\dfrac{-3}{5}\)+\(\left(\dfrac{-9}{7}+\dfrac{6}{11}\right)\):\(\dfrac{-3}{5}\)
b/ \(\left(x-\dfrac{1}{4}\right)^3=27\)