Question

Thực hiện phép tính

a. (8x⁵ - 4x³) : ( -2x³)

b. ( -2x²y³ - 3x²y² + x²y) : (\(\dfrac{-1}{3}\)x²y)

Answer 1

a) \(\left(8x^5-4x^3\right):\left(-2x^3\right)\)

\(=\left[8x^5:\left(-2x^3\right)\right]+\left[\left(-4x^3\right):\left(-2x^3\right)\right]\)

\(=-4x^2+2\)

b) \(\left(-2x^2y^3-3x^2y^2+x^2y\right):\left(\dfrac{-1}{3}x^2y\right)\)

\(=\left[\left(-2x^2y^3\right):\left(\dfrac{-1}{3}x^2y\right)\right]+\left[\left(-3x^2y^2\right):\left(\dfrac{-1}{3}x^2y\right)\right]+\left[x^2y:\left(\dfrac{-1}{3}x^2y\right)\right]\)

\(=6y^2+9y+\left(-3\right)\)

\(=6y^2+9y-3\)