a) \(\dfrac{x^2+2x}{x+2}=\dfrac{x\left(x+2\right)}{x+2}=x\)
b) \(\dfrac{5x+4-3\left(x-2\right)}{3\left(x+5\right)}=\dfrac{5x+4-3x+6}{3\left(x+5\right)}=\dfrac{2x+10}{3\left(x+5\right)}=\dfrac{2\left(x+5\right)}{3\left(x+5\right)}=\dfrac{2}{3}\)
a) Ta có: \(\dfrac{x^2}{x+2}+\dfrac{2x}{x+2}\)
\(=\dfrac{x^2+2x}{x+2}\)
\(=\dfrac{x\left(x+2\right)}{x+2}=x\)