Goi AM la dg trung truc BC
Xet ΔABM va ΔACM co:
AM chung
∠AMB=∠AMC (=90 do)(AM la dg trung truc BC)
BM=CM ( AM la dg trung truc BC)
⇒ΔABM = ΔACM (c.g.c)
⇒∠ABM= ∠ACM(2 goc tuong ung)
Ma ∠ABM= 40 do (GT)
⇒∠ACM = 40 do
Xet ΔABC co: ∠BAC +∠ABC+∠ACM= 180 do
Vi ∠ABM=∠ACM=40 do(CMT)
⇒∠BAC= 180do - 40do -40do
∠BAC=100do
(HINH VE MINH HOA)