\(\sqrt{\dfrac{1}{125}}.\sqrt{\dfrac{32}{35}}:\sqrt{\dfrac{56}{225}}=\sqrt{\dfrac{1}{125}.\dfrac{32}{35}:\dfrac{56}{225}}=\sqrt{\dfrac{36}{1225}}=\dfrac{6}{35}\)
\(\sqrt{\dfrac{1}{125}}.\sqrt{\dfrac{32}{35}}:\sqrt{\dfrac{56}{225}}=\sqrt{\dfrac{1}{125}.\dfrac{32}{35}:\dfrac{56}{225}}=\sqrt{\dfrac{36}{1225}}=\dfrac{6}{35}\)
\(\sqrt{\dfrac{1}{125}}.\sqrt{\dfrac{32}{35}}:\sqrt{\dfrac{56}{225}}\)
Tính.
B1: Tính:
a, \(\sqrt{72}\div\sqrt{8}\)
b, \((\sqrt{28}-\sqrt{7}+\sqrt{112})\div\sqrt{7}\)
B2: Tính:
a, \(\sqrt{\dfrac{49}{8}}\div\sqrt{3\dfrac{1}{8}}\)
b, \(\sqrt{54x}\div\sqrt{6x}\)
c, \(\sqrt{\dfrac{1}{125}}\times\sqrt{\dfrac{32}{35}}\div\sqrt{\dfrac{56}{225}}\)
giúp em với ạ , em cảm mơn
tính \(B=\dfrac{1}{\sqrt{5}}+\dfrac{1}{\sqrt{5}+\sqrt{10}}+......+\dfrac{1}{\sqrt{220}+\sqrt{225}}\)
tính:
a) \(\sqrt{\dfrac{1}{8}}.\sqrt{2}.\sqrt{125}.\sqrt{\dfrac{1}{5}}\)
b)\(\sqrt{\sqrt{2}-1}.\sqrt{\sqrt{2}+1}\)
c) \(\sqrt{11-6\sqrt{2}}.\sqrt{11+6\sqrt{2}}\)
d) \(\sqrt{12-6\sqrt{3}}.\sqrt{\dfrac{1}{3-\sqrt{3}}}\)
e) \(\dfrac{\sqrt{15}-\sqrt{6}}{\sqrt{35}-\sqrt{14}}\)
f) \(\dfrac{2\sqrt{15}-2\sqrt{10}+\sqrt{6}-3}{2\sqrt{5}-2\sqrt{10}-\sqrt{3}+\sqrt{6}}\)
g) \(\left(\dfrac{1}{5-2\sqrt{6}}+\dfrac{2}{5+2\sqrt{6}}\right)\left(15+2\sqrt{6}\right)\)
1,Rút gọn
\(\sqrt[3]{3+\sqrt{9+\dfrac{125}{27}}}-\sqrt[3]{-3+\sqrt{9+\dfrac{125}{27}}}\)
tính
a.\(\sqrt{\dfrac{289}{225}}\)
b.\(\sqrt{2\dfrac{14}{25}}\)
c.\(\sqrt{\dfrac{0,25}{9}}\)
d.\(\sqrt{\dfrac{8,1}{1,6}}\)
Tính:
a. \(\sqrt{\dfrac{289}{225}};\) b. \(\sqrt{2\dfrac{14}{25}};\) c. \(\sqrt{\dfrac{0,25}{9}};\) d. \(\sqrt{\dfrac{8,1}{1,6}}.\)
Rút gọn biểu thức
E = \(\dfrac{x+2\sqrt{x}+1}{\sqrt{x}+1}+\dfrac{x-\sqrt{x}}{\sqrt{x}-1}\)
F = \(\dfrac{2\sqrt{x}}{\sqrt{x}+3}-\dfrac{\sqrt{x}+1}{3-\sqrt{x}}-\dfrac{3-11\sqrt{x}}{x-9}\)
G = \(\dfrac{\sqrt{x}+3}{\sqrt{x}-2}-\dfrac{\sqrt{x}-1}{\sqrt{x}+2}+\dfrac{4\sqrt{x}-4}{4-x}\)
Trục căn thức ở mẫu:
B = \(\dfrac{1+\sqrt{5}}{2-\sqrt{5}}\) C = \(\dfrac{5-\sqrt{x}}{2\sqrt{x}}\)
D = \(\dfrac{\sqrt{a}+1}{2\sqrt{a}-1}\) E = \(\dfrac{15}{5\sqrt{3}-3\sqrt{5}}\)