Question

\(\sqrt{3x-2}\)=\(\sqrt{5+2x}\)

Answer 1

`sqrt{3x-2}=sqrt{5+2x}`

Điều kiện:`{(3x-2>=0),(2x+5>=0):}<=>x>=2/3`

`<=>3x-2=5+2x`

`<=>x=7(tm)`

Vậy `S={7}`

Answer 2

ĐKXĐ: \(\left\{{}\begin{matrix}3x-2\ge0\\5+2x\ge0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x\ge\dfrac{2}{3}\\x\ge-\dfrac{5}{2}\end{matrix}\right.\)

\(\sqrt{3x-2}=\sqrt{5+2x}\\ \Rightarrow3x-2=5+2x\\ \Rightarrow x=7\)

Answer 3

Hai bn hay quá