Ta có: \(\sqrt{3+\sqrt{5}}+\sqrt{7-3\sqrt{5}}-\sqrt{2}\)
\(=\frac{\sqrt{6+2\sqrt{5}}+\sqrt{14-6\sqrt{5}}-2}{\sqrt{2}}\)
\(=\frac{\sqrt{\left(\sqrt{5}+1\right)^2}+\sqrt{\left(3-\sqrt{5}\right)^2}-2}{\sqrt{2}}\)
\(=\frac{\sqrt{5}+1+3-\sqrt{5}-2}{\sqrt{2}}\)(vì \(\left\{{}\begin{matrix}\sqrt{5}>1>0\\3>\sqrt{5}\end{matrix}\right.\))
\(=\frac{2}{\sqrt{2}}=\sqrt{2}\)