\(A=\left(2\cdot\dfrac{8}{11}-1\cdot\dfrac{-5}{11}\right)^2=\left(\dfrac{16}{11}+\dfrac{5}{11}\right)^2=\left(\dfrac{21}{11}\right)^2=\dfrac{441}{121}\)
\(B=\left(4+1\right)\left(\dfrac{64}{121}+\dfrac{25}{121}\right)=5\cdot\dfrac{89}{121}\)
mà \(441< 5\cdot89\)
nên A<B