Ta có: \(10A=\frac{10^{20}+10}{10^{20}+1}=1+\frac{9}{10^{20}+1}\)
\(10B=\frac{10^{21}+10}{10^{21}+1}=1+\frac{9}{10^{21}+1}\)
Vì \(\frac{9}{10^{20}+1}>\frac{9}{10^{21}+1}\Rightarrow1+\frac{9}{10^{20}+1}>1+\frac{9}{10^{20}+1}\)
\(\Rightarrow10A>10B\)
\(\Rightarrow A>B\)
Vậy A > B