\(sin^2\dfrac{A}{2}=\dfrac{b-c}{2b}\)
\(\Leftrightarrow\dfrac{1-cosA}{2}=\dfrac{b-c}{2b}\)
\(\Leftrightarrow1-\dfrac{b^2+c^2-a^2}{2bc}=\dfrac{b-c}{b}=1-\dfrac{c}{b}\)
\(\Leftrightarrow b^2+c^2-a^2=2c^2\)
\(\Leftrightarrow a^2+c^2=b^2\)
Tam giác vuông tại B