Câu hỏi của Nguyen Ankem

Question

rút gọn

(x-y+z)2+(z-y)2+2(x-y+z)(y-z)???????????????????

Nguyễn Thị Thảo · Accepted Answer

(x-y+z)2+(z-y)2+2(x-y+z)(y-z)

=(x-y+z)2+2(x-y+z)(y-z)+(y-z)2

= (x-y+z+y-z)2=x2Câu trả lời: (x-y+z)2+(z-y)2+2(x-y+z)(y-z)

=(x-y+z)2+2(x-y+z)(y-z)+(y-z)2

= (x-y+z+y-z)2=x2

Bùi Mạnh Khôi · Answer

$\left(x-y+z\right)^2+\left(z-y\right)^2+2\left(x-y+z\right)\left(y-z\right)$

$=\left(x-y+z\right)^2+\left(y-z\right)^2+2\left(x-y+z\right)\left(y-z\right)$

$=\left(x-y+z+y-z\right)^2$

$=x^2$Câu trả lời: $\left(x-y+z\right)^2+\left(z-y\right)^2+2\left(x-y+z\right)\left(y-z\right)$

$=\left(x-y+z\right)^2+\left(y-z\right)^2+2\left(x-y+z\right)\left(y-z\right)$

$=\left(x-y+z+y-z\right)^2$

$=x^2$

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