Ta có:
\(A=\left(x-4\right)\left(x-2\right)-\left(x-1\right)\left(x-3\right)\)
\(\Rightarrow A=x^2-2x-4x+8-\left(x^2-3x-x+3\right)\)
\(\Rightarrow A=x^2-2x-4x+8-x^2+3x+x-3\)
\(\Rightarrow A=-2x+5\) (1)
Thay \(x=\dfrac{7}{4}\) vào(1) ta có:
\(A=-2.\left(\dfrac{7}{4}\right)+5=\dfrac{-7}{2}+5=\dfrac{3}{2}\)
Chúc bạn học tốt!!!