\(\dfrac{\left(3x+2\right)^2-\left(x+2\right)^2}{x^3-x^2}\)
=\(\dfrac{9x^2+12x+4-x^2+4x-4}{x^2\left(x-1\right)}\)
=\(\dfrac{8x^2+16x}{x^2\left(x-1\right)}\)=\(\dfrac{8x\left(x+1\right)}{x^2\left(x-1\right)}\)=\(\dfrac{8\left(x+1\right)}{x\left(x-1\right)}\)
\(\dfrac{\left(3x+2\right)^2-\left(x+2\right)^2}{x^3-x^2}\)
\(=\dfrac{\left(3x+2-x-2\right)\left(3x+2+x+2\right)}{x^2\left(x-1\right)}\)
\(=\dfrac{2x\left(4x+4\right)}{x^2\left(x-1\right)}=\dfrac{8x\left(x+1\right)}{x^2\left(x-1\right)}=\dfrac{8\left(x+1\right)}{x\left(x-1\right)}\)
Chúc bạn học tốt!!
