Question

Rút gọn biểu thức \(D=\frac{x^6-y^6}{\left(x-y\right)\left(x^4+x^2y^2+y^4\right)}\)

Answer 1

\(D=\frac{x^6-y^6}{\left(x-y\right)\left(x^4+x^2y^2+y^4\right)}=\frac{\left(x^2\right)^3-\left(y^2\right)^3}{\left(x-y\right)\left(x^4+x^2y^2+y^4\right)}=\frac{\left(x^2-y^2\right)\left[\left(x^2\right)^2+x^2y^2+\left(y^2\right)^2\right]}{\left(x-y\right)\left(x^4+x^2y^2+y^4\right)}=\frac{\left(x^2-y^2\right)\left(x^4+x^2y^2+y^4\right)}{\left(x-y\right)\left(x^4+x^2y^2+y^4\right)}=\frac{x^2-y^2}{x-y}\)

Gọn thế này được chưa???