Ôn tập chương 1: Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
Rút gọn các biểu thức sau:
a) \(2\sqrt{28}+2\sqrt{63}-3\sqrt{175}+\sqrt{112}-\sqrt{20}\)
b) \(\dfrac{3\sqrt{2}-2\sqrt{3}}{\sqrt{3}-\sqrt{2}}-\dfrac{10}{1+\sqrt{6}}\)
rút gọn
a) \(\sqrt{8+\sqrt{55}}-\sqrt{8-\sqrt{55}}-\sqrt{125}\)
b) \(\left(\sqrt{7-3\sqrt{5}}\right)\left(7+3\sqrt{5}\right)\left(3\sqrt{2}+\sqrt{10}\right)\)
c) \(\left(\sqrt{14}-\sqrt{10}\right)\left(6-\sqrt{35}\right)\left(\sqrt{6+\sqrt{35}}\right)\)
rút gọnAleft(sqrt{28}-2sqrt{14}+sqrt{7}right)cdotsqrt{7}+7sqrt{8}Bsqrt{6+2sqrt{5}}-sqrt{6-2sqrt{5}}Cleft(sqrt{7}-sqrt{10}right)^2+sqrt{280}Ddfrac{sqrt{99}}{sqrt{11}}+sqrt{7}cdotsqrt{63}-sqrt{sqrt{81}}Esqrt{27}left(s-sqrt{5}right)^2cdotleft(3sqrt{48}right)giải chi tiết ra giúp mik nha,cảm ơn nhiều
Đọc tiếp
rút gọn
A=\(\left(\sqrt{28}-2\sqrt{14}+\sqrt{7}\right)\cdot\sqrt{7}+7\sqrt{8}\)
B=\(\sqrt{6+2\sqrt{5}}-\sqrt{6-2\sqrt{5}}\)
C=\(\left(\sqrt{7}-\sqrt{10}\right)^2+\sqrt{280}\)
D=\(\dfrac{\sqrt{99}}{\sqrt{11}}+\sqrt{7}\cdot\sqrt{63}-\sqrt{\sqrt{81}}\)
E=\(\sqrt{27}\left(s-\sqrt{5}\right)^2\cdot\left(3\sqrt{48}\right)\)
giải chi tiết ra giúp mik nha,cảm ơn nhiều
15 tháng 5 2021 lúc 21:55
Rút gọn:
\(2\left(\sqrt{10}-\sqrt{2}\right)\sqrt{4+\sqrt{6-2\sqrt{5}}}\)
\(\left(4\sqrt{2}+\sqrt{30}\right)\left(\sqrt{5}-\sqrt{3}\right)\sqrt{4-\sqrt{15}}\)
1) Rút gọn:
a) A sqrt{5-2sqrt{3-sqrt{3}}}-sqrt{3+sqrt{3}}+sqrt{2+sqrt{3}}
b) B sqrt{13+sqrt{2}+5sqrt{1+2sqrt{2}}}+sqrt{13+sqrt{2}+5sqrt{1+2sqrt{2}}}
c) C dfrac{sqrt{21+3sqrt{5}}+sqrt{21-3sqrt{5}}}{sqrt{21}+6sqrt{11}}+sqrt{11-6sqrt{2}}
d) D left(sqrt{8+2sqrt{10+2sqrt{5}}}+sqrt{8-2sqrt{10+2sqrt{5}}}right).sqrt{dfrac{2+2sqrt{5}}{2+sqrt{5}}}
e) E dfrac{left(27+10sqrt{2}right)sqrt{27-10sqrt{2}}-left(27-10sqrt{2}right)sqrt{27+10sqrt{2}}}{left(sqrt{sqrt{13}-3}+sqrt{sqrt{13}+3}right):sqrt{sqrt...
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1) Rút gọn:
a) A = \(\sqrt{5-2\sqrt{3-\sqrt{3}}}-\sqrt{3+\sqrt{3}}+\sqrt{2+\sqrt{3}}\)
b) B = \(\sqrt{13+\sqrt{2}+5\sqrt{1+2\sqrt{2}}}+\sqrt{13+\sqrt{2}+5\sqrt{1+2\sqrt{2}}}\)
c) C = \(\dfrac{\sqrt{21+3\sqrt{5}}+\sqrt{21-3\sqrt{5}}}{\sqrt{21}+6\sqrt{11}}+\sqrt{11-6\sqrt{2}}\)
d) D = \(\left(\sqrt{8+2\sqrt{10+2\sqrt{5}}}+\sqrt{8-2\sqrt{10+2\sqrt{5}}}\right).\sqrt{\dfrac{2+2\sqrt{5}}{2+\sqrt{5}}}\)
e) E = \(\dfrac{\left(27+10\sqrt{2}\right)\sqrt{27-10\sqrt{2}}-\left(27-10\sqrt{2}\right)\sqrt{27+10\sqrt{2}}}{\left(\sqrt{\sqrt{13}-3}+\sqrt{\sqrt{13}+3}\right):\sqrt{\sqrt{13}+2}}\)
\(\dfrac{2\sqrt{15}-2\sqrt{10}+\sqrt{6}-3}{2\sqrt{5}-2\sqrt{10}-\sqrt{3}-\sqrt{6}}\)
1. sqrt{4-sqrt{7}}-sqrt{4+sqrt{7}}+sqrt{8}
2. dfrac{sqrt{3-2sqrt{3}}}{sqrt{17-12sqrt{2}}}-dfrac{sqrt{3+2sqrt{2}}}{sqrt{17+12sqrt{2}}}
3.sqrt{7+2sqrt{6}}-sqrt{left(sqrt{6-1}right)^2}
4sqrt{5-2sqrt{6}}-sqrt{5+sqrt{24}}
5.sqrt{4sqrt{5+sqrt{3+5sqrt{48-10sqrt{7+4sqrt{3}}}}}}
6.sqrt{6+2sqrt{5-sqrt{13+sqrt{48}}}}
Đọc tiếp
1. \(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}+\sqrt{8}\)
2. \(\dfrac{\sqrt{3-2\sqrt{3}}}{\sqrt{17-12\sqrt{2}}}-\dfrac{\sqrt{3+2\sqrt{2}}}{\sqrt{17+12\sqrt{2}}}\)
3.\(\sqrt{7+2\sqrt{6}}-\sqrt{\left(\sqrt{6-1}\right)^2}\)
4\(\sqrt{5-2\sqrt{6}}-\sqrt{5+\sqrt{24}}\)
5.\(\sqrt{4\sqrt{5+\sqrt{3+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}}\)
6.\(\sqrt{6+2\sqrt{5-\sqrt{13+\sqrt{48}}}}\)
1. sqrt{4-sqrt{7}}-sqrt{4+sqrt{7}}+sqrt{8}
2. dfrac{sqrt{3-2sqrt{3}}}{sqrt{17-12sqrt{2}}}-dfrac{sqrt{3+2sqrt{2}}}{sqrt{17+12sqrt{2}}}
3.sqrt{7+2sqrt{6}}-sqrt{left(sqrt{6}-1right)^2}
4sqrt{5-2sqrt{6}}-sqrt{5+sqrt{24}}
5.sqrt{4sqrt{5+sqrt{3+5sqrt{48-10sqrt{7+4sqrt{3}}}}}}
6.sqrt{6+2sqrt{5-sqrt{13+sqrt{48}}}}
Đọc tiếp
1. \(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}+\sqrt{8}\)
2. \(\dfrac{\sqrt{3-2\sqrt{3}}}{\sqrt{17-12\sqrt{2}}}-\dfrac{\sqrt{3+2\sqrt{2}}}{\sqrt{17+12\sqrt{2}}}\)
3.\(\sqrt{7+2\sqrt{6}}-\sqrt{\left(\sqrt{6}-1\right)^2}\)
4\(\sqrt{5-2\sqrt{6}}-\sqrt{5+\sqrt{24}}\)
5.\(\sqrt{4\sqrt{5+\sqrt{3+5\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}}\)
6.\(\sqrt{6+2\sqrt{5-\sqrt{13+\sqrt{48}}}}\)
Rút gọn các biểu thức:
a) Afrac{30}{sqrt{6}+1}+frac{2}{sqrt{6}-2}-frac{6}{3-sqrt{6}}
b) Bsqrt{17-6sqrt{2}+sqrt{9+4sqrt{2}}}
c) Csqrt{8-2sqrt{7}}-sqrt{8+2sqrt{7}}
d) Dsqrt{a+1-2sqrt{a}}-sqrt{a+16-8sqrt{a}} với 1le ale16
e) Esqrt{a-1+2sqrt{a-2}}+sqrt{a-1-2sqrt{a-2}}
f) Fsqrt[3]{10+6sqrt{3}}-sqrt{3}
g) Gsqrt[3]{7+5sqrt{2}}+sqrt[3]{7-5sqrt{2}}
Đọc tiếp
Rút gọn các biểu thức:
a) A=\(\frac{30}{\sqrt{6}+1}+\frac{2}{\sqrt{6}-2}-\frac{6}{3-\sqrt{6}}\)
b) B=\(\sqrt{17-6\sqrt{2}+\sqrt{9+4\sqrt{2}}}\)
c) C=\(\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}\)
d) D=\(\sqrt{a+1-2\sqrt{a}}-\sqrt{a+16-8\sqrt{a}}\) với \(1\le a\le16\)
e) E=\(\sqrt{a-1+2\sqrt{a-2}}+\sqrt{a-1-2\sqrt{a-2}}\)
f) F=\(\sqrt[3]{10+6\sqrt{3}}-\sqrt{3}\)
g) G=\(\sqrt[3]{7+5\sqrt{2}}+\sqrt[3]{7-5\sqrt{2}}\)