Question

Rút gọn 

a, (3x+2).(3x+2) - (3x+1)\(^2\)

b, (1-4x\(^2\)).(1+4x\(^2\))-(2x+3)\(^2\)

Answer 1

a) \(\left(3x+2\right)\left(3x+2\right)-\left(3x+1\right)^2=\left(3x+2\right)^2-\left(3x+1\right)^2=\left(3x+2-3x-1\right)\left(3x+2+3x+1\right)=1.\left(6x+3\right)=6x+3\)

b) \(\left(1-4x^2\right)\left(1+4x^2\right)-\left(2x+3\right)^2=1-16x^4-4x^2-12x-9=-16x^4-4x^2-12x-8\)

Answer 2

a: \(\left(3x+2\right)\left(3x+2\right)-\left(3x+1\right)^2\)

\(=9x^4+12x+4-9x^2-6x-1\)

=6x+3

b: \(\left(1-4x^2\right)\left(1+4x^2\right)-\left(2x+3\right)^2\)

\(=1-16x^4-4x^2-12x-9\)

\(=-16x^4-4x^2-12x-8\)