Question

Qui đồng mẫu thức các phân thức:

\(a,\dfrac{1}{6x^2y^3};\dfrac{-5}{21xy^2};\dfrac{3}{14x^4y}\)

\(b,\dfrac{2}{x^3-y^3};\dfrac{2x+1}{x^2-y^2}\)

Answer 1

a: \(\dfrac{1}{6x^2y^3}=\dfrac{7x^2}{42x^4y^3}\)

\(\dfrac{-5}{21xy^2}=\dfrac{-10x^3y}{42x^4y^3}\)

\(\dfrac{3}{14x^4y}=\dfrac{3\cdot3y}{42x^4y^3}=\dfrac{9y}{42x^4y^3}\)

b: \(\dfrac{2}{x^3-y^3}=\dfrac{2}{\left(x-y\right)\left(x^2+xy+y^2\right)}=\dfrac{2\left(x+y\right)}{\left(x-y\right)\left(x+y\right)\left(x^2+xy+y^2\right)}\)

\(\dfrac{2x+1}{x^2-y^2}=\dfrac{\left(2x+1\right)}{\left(x-y\right)\left(x+y\right)}=\dfrac{\left(2x+1\right)\left(x^2+xy+y^2\right)}{\left(x-y\right)\left(x+y\right)\left(x^2+xy+y^2\right)}\)